In Plutarch Enterprises, \(70\%\) of the employees are marketers, \(20\%\) are engineers, and the rest are managers. Marketers make an average salary of \(\$50,000\) a year, and engineers make an average of \(\$80,000.\) What is the average salary for managers if the average for all employees is also \(\$80,000?\)

A. \(\$80,000\)

B. \(\$130,000\)

C. \(\$240,000\)

D. \(\$290,000\)

E. \(\$320,000\)

Answer: D

Source: Magoosh

## In Plutarch Enterprises, \(70\%\) of the employees are marketers, \(20\%\) are engineers, and the rest are managers.

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We can solve this using weighted averagesVJesus12 wrote: ↑Thu Sep 16, 2021 11:16 amIn Plutarch Enterprises, \(70\%\) of the employees are marketers, \(20\%\) are engineers, and the rest are managers. Marketers make an average salary of \(\$50,000\) a year, and engineers make an average of \(\$80,000.\) What is the average salary for managers if the average for all employees is also \(\$80,000?\)

A. \(\$80,000\)

B. \(\$130,000\)

C. \(\$240,000\)

D. \(\$290,000\)

E. \(\$320,000\)

Answer: D

Source: Magoosh

**Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + . . .**

We're told that:

The marketers (with an average annual salary of $50,000) comprise 7/10 of the group

The engineers (with an average annual salary of $80,000) comprise 2/10 of the group

The managers (with an average annual salary of $

**x**) comprise 1/10 of the group

The average salary of all groups COMBINED = 80,000

Applying the formula we get: 80,000 = (7/10)($50,000) + (2/10)($80,000) + (1/10)(

**x**)

Simplify: 80,000 = 35,000 + 16,000 + 0.1x

Simplify: 80,000 = 51,000 + 0.1x

We get: 29,000 = 0.1x

Solve: x = 290,000

Answer: D